What are the characteristics of the vector shown? magnitude of 8 and direction angle equal to 0°

magnitude of 8 and direction angle equal to 180°

magnitude of 2 StartRoot 2 EndRoot and direction angle equal to 0°

magnitude of 2 StartRoot 2 EndRoot and direction angle equal to 180°

The correct option is;

Magnitude of 8 and direction angle equal to 0°

Step-by-step explanation:

The magnitude of a vector is given by the distance from the initial point of the vector, (which id the starting point) to the final point of the vector, which is the end point of the vector

From the graph, the starting point of the vector = (-2, 2·√2)

The end point of the vector from the graph = (6, 2·√2)

The magnitude of the vector = √(6 - (-2))² = 6 - (-2) = 6 + 2 = 8

The direction of the vector = arctan((The y-component of the vector)/(The y-component of the vector))

∴ The direction of the given horizontal vector = arctan(0/8) = arctan(0) = 0°

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step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.