A pair of dice is tossed. what is the probability of getting sum of 5 or 9? A)7/9
B)5/9
C)1/9
D)2/9

Step-by-step explanation:

Given:

A pair of dice

Required

Determine the probability of a sum of 5 or 9

Let the sample space of the first die be S1 and the second, S2

--- 6 outcomes

 --- 6 outcomes

Number of sample space, n is:

Next, we list out all possibilities of obtaining a sum of 5

n(Sum5 )= 4

Next, we list out all possibilities of obtaining a sum of 9

n(Sum9)= 4

The required probability is then calculated as:

Take LCM

Simplify

c - they will have the same distribution

step-by-step explanation:

this is the only one that could make sense. : )

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.