Bus A and Bus B leave the bus depot at 5 pm. Bus A takes 30 minutes to complete its route once and bus B takes 35 minutes to complete its route once. If both buses continue to repeat their route, at what time will they be back at the bus depot together?

8:30 pm

Step-by-step explanation:

Bus A and Bus B leave the bus depot at 5 pm. Bus A takes 30 minutes to complete its route once and bus B takes 35 minutes to complete its route once. If both buses continue to repeat their route, at what time will they be back at the bus depot together?

We solve the above question using the Lowest Common Multiple Method.

We find the Multiples of 30 minutes and 35 minutes

Multiples of 30:

30, 60, 90, 120, 150, 180, 210, 240, 270

Multiples of 35:

35, 70, 105, 140, 175, 210, 245, 280

Therefore,

LCM(30, 35) = 210

The Lowest Common Multiple = 210. This means that bus A and bus B will be back at the same depot together after 210 minutes.

We add 210 minutes to 5pm

5 pm + 210 minutes

= 5 pm + 3 hours 30 minutes

= 8:30 pm

Bus A and Bus B will be back at the depot together by 8:30 pm.

no pictures of the graph

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation: