A croissant a cup of coffee and a fruit bowl from Kelly's coffee cart cost a total of $5.50 and a croissant cost twice as much as a cup of coffee Kelly post a notice announcing that effective next week the price of a croissant will go up 25% and the price of coffee will go up 20% after the increase the total price of the purchase will be $6.03. Find the cost of each item before the increase.

cost of Croissant =$ 1.5142

cost of Coffee=$0.7571

cost of fruit bowl = $3.229

Step-by-step explanation:

Step 1

A croissant, a cup of coffee, and a fruit bowl cost $5.50 also  a croissant costs twice as much as a cup of coffee

so let cost of a cup of coffee=C

cost of croissant=2C

cost of fruit bowl = F

Such that  

C+2C+F= 5.50

3C+F=5.50equation 1

Also, effective next week, the price of a croissant will go up 25% and the

price of coffee will go up 20%  Giving us that

new cost of croissant=(2C)(1+25/100)=2.5C

new price of coffee=(C)(1+20/100)=1.20C

new price of fruit bowl still remains unchanged =F

such that

2.5C +1.20C + F=6.03

3.7C+F=6.03 equaton 2

Step 2

3C+F=5.50equation 1  

3.7C+F=6.03 equaton 2

By elimination method, we subtract eqn 1 from eqn 2

3.7C - 3C + F -F=6.03-5.5

0.7 C=0.53

C= 0.53/0.7

C=0.7571

2C= 1.5142

3C+F=5.50

3 X 0.7571 + F= 5.50

2.27 + F= 5.50

F= 5.50-2.271= 3.229

cost of Croissant =$ 1.5142

cost of Coffee=$0.7571

cost of fruit bowl = $3.229

answer is x<

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step-by-step explanation:

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