Team Z can do the work in 26 days, and working together Team Z and Y can do the same work in 14 days. How many days would it take for Y alone to do the work? Round your answer to the nearest whole number.

30 days

Step-by-step explanation:

The above question is solved as shown below:

Working together Team Z and Y can do the same work in 14 days.

1/Team Y + 1/Team Z = 1/14 days

Team Z can do the work in 26 days,

Hence:

1/Team Y + 1/26 days = 1 /14 days

= 1/ Team Y + 1/26 = 1/14

1/Team Y = 1/14 - 1/26

The Lowest Common Denominator = 182

Hence:

1/Team Y = 13 - 7/182

1/Team Y = 6/182

Cross Multiply

Team Y × 6 = 1 × 182

Team Y = 182/6

Team Y = 30.33 days

Approximately to the nearest whole number = 30 days

Therefore, Team Y alone can do the job in 30 days

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

won't that be plagrisim thought?

step-by-step explanation: