An election for favorite lunch snack is between Apples, Beets, and Carrots. Students voted for their top three from best to least. The results are: ABC : 41 BAC : 26 CAB : 42 How many votes will A have in total after B is eliminated due to the Hare method

after eliminating B due to Hare Method, A will have a total of 67 VOTES

Step-by-step explanation:

Given that;

The results are

ABC : 41

BAC : 26

CAB : 42

NOW

A>B>C = 41 ⇒ A has 41 votes

B>A>C = 26 ⇒ B has 26 votes

C>A>B = 42 ⇒ C has 42 votes

According to Hare method, least votes gainers will be eliminated and once eliminated, his/her/its votes will be transferred to the next choice of person/thing.

based on the question; B will be eliminated

so we have;

A>B>C = 41 ⇒ A has 41 votes

B>A>C = 26 ⇒ B has 26 votes

we eliminate B, the votes are transferred to the next (A)

A>C = 26 ⇒ A has 26 votes

C>A>B = 42 ⇒ C has 42 votes

SO in total

A votes = 41 + 26 = 67 VOTES

Therefore after eliminating B due to Hare Method, A will have a total of 67 VOTES

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step-by-step explanation: