Please help me with this

Square E: s = 5, A = 25

Square F: P = 32, A = 64

Step-by-step explanation:

P = 4s

20 = 4s

s = 5 <-- Answer for side length of Square E

P = 4s

P = 4(8)

P = 32 <-- Answer for the perimeter of Square F

A = s^2

A = 5^2

A = 25 <-- Answer for the Area of Square E

A = s^2

A = 8^2

A = 64 <-- Answer for the Area of Square F

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.