3T Which equation shows that the Pythagorean identity is true for 0 =
Select the equation that is in the form sin? (3pi/2) +cos² (3pi/2) = 1.

A. 1^2 + 0^2 = 1
B. (-1)^2 + 0^2 = 1
C. 0^2 + 1^2 = 1
D. 0^2 + (-1)^2 = 1

50-60=10

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

answer:  

step-by-step explanation:

odd numbers are only divisible by 1 and itself.

even numbers are divisible by more than 1 and itself.

for example 6 is even because it is divisible by more than 1 and its self. 1 x 6= 6 ; 2 x 3= 6

and 7 is odd because only 7 x 1 equals seveb