X+2y=13
3x-5y=6
what is (x, y)?

(7, 3)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

x + 2y = 13

3x - 5y = 6

Step 2: Rewrite Systems

x + 2y = 13

Subtract 2y on both sides:                    x = 13 - 2y

Step 3: Redefine Systems

x = 13 - 2y

3x - 5y = 6

Step 4: Solve for y

Substitution

Substitute in x:                    3(13 - 2y) - 5y = 6Distribute 3:                         39 - 6y - 5y = 6Combine like terms:           39 - 11y = 6Isolate y term:                     -11y = -33Isolate y:                              y = 3

Step 5: Solve for x

Define equation:                    x + 2y = 13Substitute in y:                       x + 2(3) = 13Multiply:                                  x + 6 = 13Isolate x:                                 x = 7

The answer would be c.hope this .

Answer: b 2 = 1.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

therefore, b 2= 1.