Which equation represents a line that passes through (2, ) and has a slope of 3? O y-2= 3(x +)
O y-3=2(x +)
Oy+= 3(x-2)
O y+=2(x–3)

y - 3 = 2 (x + 1/2)

Step-by-step explanation:

y= mx + b

M is your slope and B is your y-intecept.

Hope this helped!! <3

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐