The value of a second-hand car is £8000 Each year it loses 20% of it value at the start of this year. work out its value in 5 years time.

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£2,621.44

Step-by-step explanation:

Original cost of car = £8000

If it looses 20% of its value yearly

Value at the end of first year

80% * 8000

= 0.8 * 8000

= 6400

Value at the end of second year

80% * 6400

= 0.8 * 6400

= 5120

Value at the end of third year

80% * 5120

= 0.8 * 5120

= 4096

Value at the end of fourth year

80% * 4096

= 0.8 * 4096

= 3,276.8

Value at the end of fifth year

80% * 3,276.8

= 0.8 * 3,276.8

= 2,621.44

Hence the value in 5 years time will be £2,621.44

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation:

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: