A local cal dealership placed an advertisement in the newspaper in the shape of a rectangle. The next week the car dealership replaced the original advertisement with a new one, but the dimensions of the new ad were half the original dimensions. How much is the area of the original advertisement than the replacement ad?

  answer:

  write 548 as 500 + 40 + 8. multiply each addend by 5. then add the three products to get 2,740.

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.