Because of a virus introduced into a bacterial culture, the population of the bacteria decreasedfrom 3000 to 1000 in 50 minutes. Assuming exponential decay, determine how many bacteriawill remain after 2 hours from the beginning of the experiment.(Note: First give an exactanswer, then round it to the nearest integer.)

208

Step-by-step explanation:

Given that;

Given that;

y= a(1 - b)^t

Where;

wherein y is the final amount, a is the original amount, b is the decay factor, and x is the amount of time that has passed.

To obtain the constant b,

y= ae^-bt

Substituting values;

1000 = 3000 e^-b(50)

1000/3000 = e^b(50)

0.33 = e^b-(50)

ln (0.33) = ln(e^b(-50))

-1.1 = -50b

b= 1.1/50

b= 0.022

After two hours or 120 minutes;

y= 3000(1 - 0.022)^120

y= 207.8661772

y= 208

answer: it's a

step-by-step explanation:

the answer will be b x² +x-1

step-by-step explanation: