If R is the midpoint of TS, TR = 5x - 12, and RS = 3x + 8, find TS.

Applying the segment addition theorem, the value of TS is: 76

Given:

TR = 5x - 12

RS = 3x + 8

If T is the midpoint of TS, therefore we would have the following equation:

TR = RS

5x - 12 = 3x + 8

5x - 3x = 12 + 8

2x = 20

x = 10

TS = TR + RS (segment addition theorem)

TS = 5x - 12 + 3x + 8

TS = 5(10) - 12 + 3(10) + 8

TS = 50 - 12 + 30 + 8

TS = 76

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5x -12 = 3x +8 (set the two = each other because they are the same length)

2x- 12= 8 (subtract 3x from both sides)

2x = 20 (add 12 to both sides)

x=10 (what x= for both expressions)

5(10) -12 (plug it into the first one to see what the length is and to see they're =

50 - 12 ( I already multiplied, now subtract)

38 (what the length of TR is)

3(10) +8 (plug it in again but into the other expression)

30+8 (multiply and add)

38 (the two have the same answer, so the x-value is correct.)

38+38= 76 (add the lengths of RS and TR and you get the length of TS)

Step-by-step explanation:

I hope this helps :)

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation:

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05