Whats the slope of a line if its plotted (0,0) and (3,6), find the y-intercept of the line. write an equation for the line using your answers. find one more point that lies on the line. explain why that point is also a solution to the function. ( explain your answers so i could understand it more) guys!

To find the slope you do the method
Y2-Y1

X2-X1
So you do 6-0=6 and 3-0=3. That would be 6/3 and then, you simplify it. Your slope is 2.
To find the y-intercept you have to do the point slope form, then, you do the slope intercept form
Y-Y1=m(x-x1)
You do y-6=2(x-3)
Y-6=2x+(-6)
You add six to both sides
The equation is y=2x
The y-intercept is -6
One more point on the line would be (4,8). Because if you look at the slope it is 2/1. When plotting a point you look at the slope as rise over run. The two is the rise and the 1 is the run. So you go to (3,6) and add 1 to the 3. Then, you add 2 to the 6 to get (4,8). That's why that point is a solution to the function. You could also do (2,4) if you did the opposite and subtracted the 2 and 1 to make the bottom half of the line.

Very simple.

so slope=rise/run so  if we plot the points and find how high and how long it went we see that the slope=6/3=2
slope=2

since the line goes through the origin (0,0) the y-intercept=(0,0)
and the equation is
y=mx+b
m=slope
b=how much away from the origin whic is not applicable in this problem. so
y=2x

Im sorry but what on