A rectangular parking lot is surrounded on its perimeter by a fence that is 1,200 feet long. If the length of the rectangular parking lot is 5 times its width, w, which equation can be used to find the width of the parking lot?

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .