For a specific location in a particularly rainy city, the time a new thunderstorm begins to produce rain (first drop time) is uniformly distributed throughout the day and independent of this first drop time for the surrounding days. Given that it will rain during some period on both of the next two days, what is the probability that the first drop of rain will be felt between 9:15 AM and 2:50 PM on both days

The required probability = 0.0541

Step-by-step explanation:

From the given information:

The probability that it will rain throughout the day is uniformly distributed & independent of the surrounding days.

Assuming that (P₁)  represents the probability that it will rain between 9:15 am to 2:50 pm on day 1.

The time interval is 5 hours 35 minutes long.

= 5.583333 hours long

Thus;

P₁ = 5.583333/24

P₁ = 0.2326

Assuming that (P₂)  represents the probability that it will rain between 9:15 am to 2:50 pm on day 2.

P₂ = P₁ = 0.2326

Therefore, the total probability = P₂ × P₁  (independent events)

= 0.2326 × 0.2326

= 0.05410276

≅ 0.0541

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.