A bike lock has a 3 digit combination. Each character can be any digit from 3-8. The only restriction is that all 3 characters cannot be the same (e. G.555,666,777...). How many combinations are possible?

The number of possible combinations is 180

Step-by-step explanation:

The numbers to select from are 3-8

These are 6 numbers

Now, the restriction we have is that the 3 characters cannot be the same

For the first character, we have 6 choices;

For the second character, we have another 6 choices

For the last character, since it cannot be the same, we can only have 5 choices

So the possible number of choices will be;

6 * 6 * 5 = 189 combinations

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

step-by-step explanation:

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.