The system of equations can be solved using linear combination to eliminate one of the variables.

2x − y = −4 → 10x − 5y = −20
3x + 5y = 59 → 3x + 5y = 59
13x = 39

which equation can replace 3x + 5y = 59 in the original system and still produce the same solution?

2x – y = –4

10x – 5y = –20

7x = 39

13x = 39

Option D is correct

13x = 39

Step-by-step explanation:

Given the system of equation:

2x − y = −4            ....[1]

3x + 5y = 59         ....[2]

using linear combination to eliminate one of the variables.

multiply equation [1] by 5 to both sides we have;

      ....[3]

Add equation [2] and [3] to eliminate y ans solve for x.

13x = 39

Therefore, an equation can replace 3x + 5y = 59 in the original system and still produce the same solution is, 13x = 39

this is a very good question

step-by-step explanation:

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