A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of a second. f(x) = -16x^2+272x+110

The time that the rocket will hit the ground will be:

Step-by-step explanation:

Given the expression

Here:

We know that when the rocket will hit the ground, the height will get y = 0

i.e.

solving for x to determine the time that the rocket takes when it will hit the ground.

so

subtract 110 from both sides

Divide both sides by -16

solving

x = 17.40 seconds

also solving

x = -0.40 seconds

As time can not be negative.

Thus, the value of x = 17.40 seconds

Therefore, the time that the rocket will hit the ground will be:

i think is g(1)=-1.

hope that i can