A company that manufactures storage bins for grains made a drawing of a silo. The silo has a conical base, as shown below: The figure shows a silo shaped as a closed cylinder with a conical end. The diameter of the silo is 4 ft, the length of the cyl

Which of the following could be used to calculate the total volume of grains that can be stored in the silo?

π(6ft)2(2ft) + one over three π(10.5ft − 6ft)2(2ft)
π(2ft)2(6ft) + one over three π(10.5ft − 6ft)2(2ft)
π(6ft)2(2ft) + one over three π(2ft)2(10.5ft − 6ft)
π(2ft)2(6ft) + one over three π(2ft)2(10.5ft − 6ft)

π(2ft)2(10ft) + one over three π(2ft)2(13ft − 10ft)

Explanation:

Given the following:

Diameter of silo = 4ft

Length of silo (h)= 13ft

Length of cylindrical part (h)= 10ft

Therefore, length of conical part(h) = (13 - 10) = 3ft

Radius(r) = diameter/2 = 4/2 = 2

The volume of a cylinder :

πr^2h

π(2ft)^210ft = π4ft10ft

The volume of cone :

1/3πr^2h

1/3π(2ft)^23ft = 1/3π4ft3ft

Therefore, the total volume of grains that can be stored in the silo equals

The volume of cylinder + volume of a cone

π(2ft)^210ft + 1/3π(2ft)^2(13 - 10)ft

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4