subject
Mathematics, 17.12.2020 07:50 ineedhelpplz40

The perimeter of a square is 20 meters. Explain how you can use this information to find the area of the same square.

Combine the formula for the perimeter and area of a square into a single formula. Then substitute P=20 and solve for s using the order of operations.

You can use the formula for the perimeter of a square to find the length of one of the square's sides. Then substitute that information into the formula for the area of a square and solve.

You can determine the length of one of the square's sides from the given information. Substitute the value for into each of the formulas for a square's perimeter and area. The value of P will be equal to the value of A .

Use the formula for the area of a square to find the length of a single side of the square. Then substitute that information into the formula for the perimeter of a square and solve.

ansver
Answers: 1

Another question on Mathematics

question
Mathematics, 21.06.2019 18:30
Atriangle with all sides of equal length is a/an triangle. a. right b. scalene c. equilateral d. isosceles
Answers: 2
question
Mathematics, 21.06.2019 20:30
Someone answer asap for ! michele pushes a box d meters across a floor. she uses a force f, in newtons, to push the box. she pushes the box for t seconds. the formula p = fd/t calculates the power, p, in watts, that it takes for michele to complete the task. solve the formula for d.
Answers: 2
question
Mathematics, 21.06.2019 22:20
Let f(x) = 5/x and g(x)=2x2+5x. what two numbers are not in the domain of f o g
Answers: 2
question
Mathematics, 21.06.2019 22:30
Factor the polynomial by its greatest common monomial factor.
Answers: 1
You know the right answer?
The perimeter of a square is 20 meters. Explain how you can use this information to find the area of...
Questions
question
English, 25.02.2021 04:40
question
Mathematics, 25.02.2021 04:40
question
Biology, 25.02.2021 04:40
question
Mathematics, 25.02.2021 04:40
question
Mathematics, 25.02.2021 04:40
Questions on the website: 13722367