On interval 0 ≤ x < 2π, where are the x-intercepts of y = cos(2x)? StartFraction pi Over 2 EndFraction and StartFraction 3 pi Over 2 EndFraction
0, π, and 2π
StartFraction pi Over 2 EndFraction, pi and StartFraction 3 pi Over 2 EndFraction

actually your concept is wrong

step-by-step explanation:

150% of x =300

150x=300×100

x=(300×100)÷150

x=200

b. b < 1 might be the correct answer

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x

i dont know

step-by-step explanation:

the reason i dont know is because i have not taken this class and for that reason i haven't learned this stuff

hope i could