Solve the equation by completing the square 3s^2+8s=2s-9

S=
S=

I need this to be answer ASAP and with a step by step explanation please !

x = - 1 ± i

Step-by-step explanation:

Given

3s² + 8s = 2s - 9 ( subtract 2s - 9 from both sides )

3s² + 6s + 9 = 0

To complete the square

The coefficient of the s² term must be 1, so factor out 3 from 3s² + 6s

3(s² + 2s) + 9 = 0

add/subtract ( half the coefficient of the s- term )² to s² + 2s

3(s² + 2(1)s + 1 - 1) + 9 = 0

3(s + 1)² - 3 + 9 = 0

3(s + 1)² + 6 = 0 ( add 6 to both sides )

3(s + 1)² = - 6 ( divide both sides by 3 )

(s + 1)² = - 2 ( take the square root of both sides )

s + 1 = ± = ± i ( subtract 1 from both sides )

s = - 1 ± i

Thus

s = - 1 + i , s = - 1 - i

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)