Claudia spends $2.15 day for lunch. Her cafeteria lunch account has a balance of 48.00.Which equation can be used to determine the maximum number of days, d,that she can eat without adding money to her lunch account?

Given :

Claudia spends $2.15 day for lunch.

Her cafeteria lunch account has a balance of 48.00 .

To Find :

The maximum number of days, d that she can eat without adding money to her lunch account.

Solution :

Number of days she can eat without adding money in her account is :

But, number of days cannot be in decimal.

Therefore, maximum number of days she can eat without adding money to her lunch is 22 days.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

answer:

step-by-step explanation: