With my math i will do anything in the world

2.
assuming that the point 'P' is the center, (0,0)
perpendicular lines have slopes that multiply to -1
y=mx+b
m=slope
given
y=-3/4x
-3/4 times what=-1
4/3
y=4/3x is the bike path equaiotn

3.
paralell lines have same slope

for  points (x1,y1) and (x2,y2)
(y2-y1)/(x2-x1)=slope

l1 slope is for points (-4,1) and (2,5)
slope is (5-1)/(2-(-4))=4/6=2/3

other one
(3,0) and (-3,k)
slope is 2/3
2/3=(k-0)/(-3-3)
2/3=k/(-6)
times both sides by -6
-4=k

hmm
find the equaitions
(2,5)
5=2/3(2)+b
5=4/3+b
11/3=b
y=2/3x+11/3 is l1

(3,0)
0=2/3(3)+b
0=2+b
-2=b
y=2/3x-2 is l2

k=-4
the slopes must be equal
l₁ equation is y=2/3x+11/3
l₂ equation is y=2/3x-2