HELP ASAP "Steve's mom gives him 50$ to spend at the mall. He must but two new pairs of pants which each cost 19$ each. He can spend the rest at an arcade where each game cost 0.75 Which inequality can be used to determine the number (n) of arcade games Steve can play?

19 + 0.75n <50

19 + 0.75, n , <50

38 + 0.75n <50

38 + 0.75, n , <50

19 + 0.75n ≤50

19 + 0.75, n is less than or equal to, 50

38 + 0.75n ≤50

bro i'm literally doing math homework right now and i don't know ANYTHING about it. so dude i def cant help u i'm sorry :')

Step-by-step explanation:

6e14 is the answer.

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!