The half-life of phosphorus-32 is approximately 24.3 days. Determine a so that A(t)=A0at describes the amount of phosphorus-32 left after t days, where A0 is the amount at time t=0. ROUND TO SIX DECIMAL PLACES.

Please help every answer has been incorrect so far.

Step-by-step explanation:

The half-life of Phosphorus-32 is approximately 24.3 days.

We have the equation:

And we would like to determine a.

First, since it is half-life, a=1/2.

Second, since the half-life for our element is 24.3 days, we need to substitute t for t/24.3. This yields:

In this way, if t=24.3, then we would have one half-life.

We can rewrite our equation as:

Approximate, rouding to six decimal places. So, our function is:

Therefore, our new a is:

This will give the amount of Phosphorus-32 left after t days, giving the initial amount of A₀.

the answer is b. 60. each interior angle in 120, so the exterior angle must be 60 in order to add up to 180

step-by-step explanation:

d no solution

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