Line JK passes through J (-3,11) and K (1, -3) what is the equation of line JK in point slope form? A. Y - 11 = 7/2(x-3)
B. Y + 3 = 7/2(x-1)
C. Y - 11 = -7/2(x+3)
D. Y - 3 = -7/2(x-1)

pls help

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

answer:

125 yards

explanation:

75+50=125. that is my answer

thats not a system of equations, that is a solution

since no one answered yet i will give it a shot, not completely sure tho.

i think it should be y=cos(x+2pi), (third answer, answer c)

good luck.