Bob needs $44 to buy a new pair of pants. He has already been able to save $9 and plans to work as a cook where he can earn $7 per hour. Which inequality shows the minimum number of hours, n, that Bob will have to work as a cook to earn enough to buy the pants? (5 points) a. 9 + 7n ≤ 44, so n ≤ 5

b. 9 + 7n ≥ 44, so n ≥ 5

c. 7n ≥ 44 + 9, so n ≥ 7.8

d. 7n ≤ 44 + 9, so n ≤ 7.8

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Step-by-step explanation:

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

i dont know

step-by-step explanation: