Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.

II. One and only one solution

Step-by-step explanation:

Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.

Let assume the equation is given as;

x + 3y = 11 1

x - y = -1 2

Using elimination method

Subtract equation 1 from 2

(x-x) + 3y-y = 11-(-1)

0+2y = 11+1

2y = 12

y = 12/2

y = 6

Substitute y = 6 into equation 2:

x-y = -1

x - 6 = -1

x = -1 + 6

x = 5

Hence the solution (x, y) is (5, 6)

Hence we can say the equation has One and only one solution since we have just a value for x and y

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation:

35/2 is it i think maybe