Will get brainliest, no bad answers, bad answers will be reported and/or banned. Zubin drew a circle with right triangle PRQ inscribed in it, as shown below:

The figure shows a circle with points P, Q, and R on it forming an inscribed triangle. Side PQ is a chord through the center an

If the measure of arc QR is 50°, what is the measure of angle PQR? (6 points)

75°
65°
25°
50°

Explanation:

Minor arc PR is the measure of the arc from P to R following the shortest path (along the bottom). This minor arc combines with the minor arc QR = 50 that is shown to get 180 degrees. This means minor arc PR is 130 degrees since 130+50 = 180.

Or you could solve x + 50 = 180 to get x = 130.

Once you know minor arc PR, you cut this in half according to the inscribed angle theorem. That leads to the inscribed angle PQR = 130/2 = 65.

As an alternative route, you can start with minor arc QR = 50 and cut this in half to get 25. This is the measure of inscribed angle QPR. Then subtract this from 90 since we're dealing with a right triangle. So 90-25 = 65 is the other acute angle of the right triangle, which is the measure of angle PQR.

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet