I NEED A-D ANSWERED PLEASE! 20 POINTS! A diver jumps off a diving board with an initial velocity of 4 m/s from a height of 5 m. The
equation h(t) = -4.9t^2+ 4t + 5 models the diver height in meters after t seconds.

a) About how many seconds does it take for the diver to land in the water?

b) What is the diver's height after 1 second?

c) How long does it take for the diver to reach the maximum height?

d) What is the diver's maximum height?

Step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

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step-by-step explanation:

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