Which is the equation of a line that has a slope of -5 and passes through point (-3,-1)? O y=-3x+1 O y=-3x+3 O y=-x-1 O y=-x-3 3

Note: Your answer choices are not clear, thus I have solved the complete question which anyways should be able to clear your concept.

The equation of a line that has a slope of -5 and passes through the point (-3,-1) will be:

Step-by-step explanation:

Given

We know that the slope-intercept form of the line equation is

Here:

Now, substituting m = -5 and (-3, -1) in the slope-intercept form of the line equation  to determine the y-intercept 'b'

-1 = -5(-3) + b

switch sides

-5(-3) + b = -1

15 + b = -1

b = -1 - 15

b = -16

Now, substituting m = -5 and b = -16 in the slope-intercept form of the line equation  to determine the equation of a line

y = -5x + (-16)

y = -5x - 16

Therefore, the equation of a line that has a slope of -5 and passes through the point (-3,-1) will be:

Note: Your answer choices are not clear, thus I have solved the complete question which anyways should be able to clear your concept.

step-by-step explanation: