Divide using polynomial long division. (Show your work) Hint: don’t forget the 0x
(x^3-2x^2+4) ÷ (x+3)

x^3−2x2+4x+3=x2−5x+15+−41x+3

Step-by-step explanation:

1.Divide the leading term of the dividend by the leading term of the divisor: x3x=x2.

Write down the calculated result in the upper part of the table.

Multiply it by the divisor: x2(x+3)=x3+3x2.

Subtract the dividend from the obtained result: (x3−2x2+4)−(x3+3x2)=−5x2+4.

2.Divide the leading term of the obtained remainder by the leading term of the divisor: −5x2x=−5x.

Write down the calculated result in the upper part of the table.

Multiply it by the divisor: −5x(x+3)=−5x2−15x.

Subtract the remainder from the obtained result: (−5x2+4)−(−5x2−15x)=15x

3.Divide the leading term of the obtained remainder by the leading term of the divisor: 15xx=15.

Write down the calculated result in the upper part of the table.

Multiply it by the divisor: 15(x+3)=15x+45.

Subtract the remainder from the obtained result: (15x+4)−(15x+45)=−41.

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: