Question Find the equation of the line that is perpendicular to the given line and passes through the given point.
Enter your answer in slope-intercept form (y = mx + b ) with the values of m and b given as decimals,
rounded to the nearest hundredth if necessary.
y = 10x ; (6,-4)
The equation is y =

PLEASE ANSWER QUICKLY !!!

Step-by-step explanation:

The point-slope form of equation of a line is:

                          y - y₀ = m(x - x₀)

where (x₀, y₀) is the point which the line passes through and m is the slope of the line

The product of slopes of two perpendicular lines is  -1

so if given lines slope is 10 them:

    10·m = -1

        m = -0.1

(6, -4)     ⇒    x₀ = 6,  y₀ = -4

Therefore:

               y - (-4) = -0.1(x - 6)

               y = -0.1x + 0.6 + (-4)

                y = -0.1x - 3.4

it’s the first one your welcome

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8