Is there enough information to prove that the triangles are congruent? If yes, provide the correct Triangle Congruence Postulate or Theorem and a
congruence statement.
If no, justify your answer.
Please help!!!

Skill Tests

With a partner, complete the Skill Tests for the six areas of skill-related fitness and record both your scores and your partner’s scores below. Answer the reflection questions.

My Scores:

Agility – Agility Square Test:

Speed – Stay on Your Toes Test:

Reaction Time – Ready, Set, Go Test:

Balance – Stork Stance Test:

Coordination – Off the Wall Test:

Power – Standing Long Jump Test:

Partner Scores:

Agility – Agility Square Test:

Speed – Stay on Your Toes Test:

Reaction Time – Ready, Set, Go Test:

Balance – Stork Stance Test:

Coordination – Off the Wall Test:

Power – Standing Long Jump Test:

Compare your scores to your partner’s scores. Explain the reason for any differences.

How can improving your balance and coordination affect your performance in sports or recreational activities?

What activity was the most difficult for you to perform? Why?

Describe an activity that could help improve your striking and your reaction time skills.

Select a physical activity or sport that you have never done but would like to try one day. Identify at least one element of skill-related fitness that is important to being successful in this activity.

What power-increasing activities do you need to perform regularly to improve your performance?

Yeah, theorem triangle

Step-by-step explanation:

he kicked it up? is this the answer ?

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)