A polynomial function has a root of -6 with multiplicity 1, a root of -2 with multiplicity 3, a root of 0 with multiplicity 2 and a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, which statement about the graph is true? The graph of the function is positive on (-6, -2). The graph of the function is negative on (-∞, 0). The graph of the function is positive on (-2, 4). The graph of the function is negative on (4,∞)

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  (a)  The graph of the function is positive on (-6, -2)

Step-by-step explanation:

A function of odd degree and positive leading coefficient will be negative from -∞ to the left-most zero. Here, that zero is -6. The multiplicity of that zeros is odd (1), so the sign changes to positive at that point, and remains positive until the next odd-multiplicity zero, which is -2, with multiplicity 3.

Hence the function is positive on the interval (-6, -2), matching choice A.

the dimensions are:

step-by-step explanation:

we want to find the dimensions of a rectangular box with volume of

we factor to obtain;

we rewrite the rightmost factor to obtain;

recall that:

we apply difference of two squares formula to obtain;

hence the dimensions are

i really dont know

step-by-step explanation: