The temperature was –5°C at 6:00 a. M. It increased 3 4 34 of a degree every hour for 6 hours. The temperature then increased 1 1 2 112 degrees every hour for 5 hours. What was the temperature at 5:00 p. M.?

The temperature was;

6 °C

Step-by-step explanation:

Here, we want to know the temperature at 5 pm

For the first 6 hours, we have an increase of 3/4 degree per hour

so the temperature increase in the first 6 hours will be;

6 * 3/4 = 4.5 degrees

Then we had an increase of 1 1/2 degrees per hour for 5 hours

The increase after these 5 hours will be;

3/2 * 5 = 15/2 = 7.5 degrees

Total increase is 7.5 + 4.5 = 11 degrees

We subtract the initial -5 from here

So the present temperature will be;

-5 degree + 11 degree = 6 degrees celsius

i need the table so i can see

step-by-step explanation:

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3