The sides of a square field are 28 meters. A sprinkler in the center of the field sprays a circular area with a diameter that corresponds to a side of the field. How much of the field is not reached by the sprinkler? Round your answer to the nearest hundredth. Use 3.14 for π.

168.24784 m²

Step-by-step explanation:

Area of the square:

28 x 28=784 sq. m.

Area of the circle:

π(r²)=π(14)²=196π

    =615.75216

Area not covered by the sprinkler:

784-615.75216=168.24784 m²

The sprinkler does not reach 168.56 m² of the field.

Step-by-step explanation:

Find the circular area sprayed by the sprinkler.

A=πr²Use the formula.

A=π(14)²Substitute. Use 14 for r.

A≈3.14 × 14²Substitute. Use 3.14 for π.

A≈3.14 × 196Evaluate the power.

A≈615.44Multiply.

The area of the circular area is about 615.44 ft².

Find the area of the square field.

A=s²Use the formula.

A=28²Substitute. Use 28 for s.

A=784Evaluate the power.

The area of the square field is 784 m².

Find how much of the field is not reached by the sprinkler. Subtract the circular area sprayed by the sprinkler from the area of the square field.

784 − 615.44=168.56

2x + 8

step-by-step explanation:

2

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