The population in Smalltown in 2010 was 45,230 people and is growing exponentially at a rate of 2%. What will the population be in 2030?
O 67,475
O 81.928
O 67.209
O 82.414

The first option

67475

Step-by-step explanation:

Step one:

Given data

The population in Smalltown in 2010 was 45,230

rate= 2%= 0.02

time t= 20 years

Step two:

Let P(t) = population t years after 2010  

              = 45230e^0.02t

Population in 2030 = P(20)

                                = 45230e^0.02t(20)

                                  = 45230e^0.4

                                  ≈ 67475

the two may have that, even a breakdown is probably offered

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.