The side of a cube is increasing at a rate of 2 kilometers per hour. At a certain instant, the side is 1.5. What is the rate of change of the volume of the cube at that instant (in cubic kilometers per hour)?

dV/dt = 13,5 [Km³/h]

Step-by-step explanation:

The volume f the cube is:

V = x³                 where x is a side of the cube, then tacking derivatives with respect to  time on both sides of the equation

dV/dt = 3*x² dx/dt

dx/dt = 2 km/h

at the time when the side x =  1,5 Km

dV/dt = 3* (1,5)²*2   [km³/h]

dV/dt = 13,5 [Km³/h]

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2