Emma throws an object upward from a hill that is 64 feet high. The object has an initial velocity of 48 feet per second. The function y = -16x2 + 48x + 64 represents the height of the object, y, in terms of the time elapsed after the object is thrown, x.

100feet

Step-by-step explanation:

Given the height of the object modelled by the equation

y = -16x^2 + 48x + 64

We can find the maximum height reached by the object since we are not told what to find.

The velocity of the object at its max height is zero.

dy/x = 0

dy/dx = -32x + 48

0 = -32x + 48

32x = 48

x = 48/32

x = 1.5secs

get the max height by substituting x = 1.5 into the given equation:

y = -16x^2 + 48x + 64

y = -16(1.5)^2 + 48(1.5)+ 64

y =  -36+72+64

y = 100 feet

Hence the maximum height reached by the object is 100feet

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse