Find all solutions in the interval [0, 2π) for 2 sin^2 x = sin x Option A: x = pi divided by three., two pi divided by three.

Option B: x = pi divided by two, three pi divided by two., pi divided by three., two pi divided by three.

Option C: x = 0, π, pi divided by six, five pi divided by six

Option D: x = pi divided by six, five pi divided by six

(Will mark brainliest)

D

Step-by-step explanation:

2 sin²x=sin x

2 sin² x-sin x=0

sin x(2 sin x-1)=0

sin x=0

x=0,π

2 sin x-1=0

2 sin x=1

sin x=1/2= sin π/6,sin (π-π/6)

x=π/6,5π/6

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.

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step-by-step explanation:

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