Help me pls Square RSTU is inscribed in circle P. Given the coordinates for the vertices of the square, find the equation of circle P.
R(0, 4), S(6, 2), T(4, -4), and U(-2, -2)

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  (x -2)² +y² = 20

Step-by-step explanation:

The center of the circle is the midpoint of either diagonal of the square. The midpoint of RT is ...

  (R +T)/2 = ((0, 4) +(4, -4))/2 = (4, 0)/2 = (2, 0)

The square of the radius is the square of the distance between the center any any point on the circle. The distance (squared) from the center to R is ...

  d² = (x2 -x1)² +(y2 -y1)²

  d² = (0 -2)² +(4 -0)² = 4 +16 = 20

The circle with radius² = r² and center (h, k) has equation ...

  (x -h)² +(y -k)² = r²

Our circle has (h, k) = (2, 0) and r² = 20, so the equation is ...

  (x -2)² +y² = 20

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says