Solve the inequality please - 3 (2- b) < 10- 3 (b- 6) Thank you so much

Step-by-step explanation:

-3(2 - b) < 10 - 3(b - 6)

-6 - 3b < 10 - 3b + 18

-6 < 28

Hence the inequality is true for any real values of b.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3