A line passes through A(6,5) and B(4,2) find equation of a line parallel to AB and passes through (7,10)

2y = 3x-1

Step-by-step explanation:

We start by calculating the slope of AB

m = (y2-y1)/(x2-x1) = (2-5)/(4-6) = 3/2

Since the two lines are parallel, then their slopes are equal

We use the point-slope form to get the equation

That will be;

y-y1 = m(x-x1)

y-10 = 3/2(x-7)

y = 3x/2-21/2+ 10

Multiply through by 2

2y= 3x -21 + 20

2y = 3x-1