I dont get this so cant help daughter

1.

We are told that the coordinates of the image are of the formula:

P'(x-2 , y-3) where x and y are the actual points and x-2 and y-3 are the reflections

Finding the coordinates of point A:

We are given that the coordinates of reflection of A are: A'(-4 , 3)

we also know that reflected point follow the formula: P'(x-2 , y-3)

So, the points of A'(-4 , 3) follow the formula P'(x-2 , y-3)

So, their respective x and y coordinates will be equal

Hence,

x - 2 = -4

x  = -2                 [adding 2 on both sides]

Also,

y - 3 = 3

y  = 6                 [adding 3 on both sides]

Therefore, the coordinates of A are A(-2,6)

Finding the coordinates of B:

We are given the coordinates of B' are B'(-4 , 2)

So,

x - 2 = -4

x = -2             [adding 2 on both sides]

also,

y-3 = 2

y = 5             [adding 5 on both sides]

Therefore, the coordinates of B are: B(-2,5)

Finding the coordinates of C:

We are given that the coordinates of reflection of C are: C'(-2,3)

Using the general formula given in the question:

x - 2 = -2  

x = 0            [adding 2 on both sides]

y - 3 = 3

y = 6            [adding 3 on both sides]

Therefore, the coordinates of C are: C(0,6)

Finally, the coordinates of A, B and C are:

A(-2,6)   ,    B(-2,5)   ,    C(0,6)

2.

Reflecting the pre-image along the x-axis

To reflect along x-axis, we multiply the y-coordinate by -1

Coordinates of the pre-image:

A(-2,6)   ,    B(-2,5)   ,    C(0,6)

Coordinates of points reflected along the x-axis:

A(-2,-6)   ,    B(-2,-5)   ,    C(0,-6)

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v