Solve the following system of equations algebraically... NEED HELP PLZ

flour $42 , bag of sugar $58

Step-by-step explanation:

let f represent flour and s represent sugar, then

7f + 5s = 584 → (1)

5f + 3s = 384 → (2)

Multiplying (1) by 3 and (2) by - 5 and adding will eliminate s

21f + 15s = 1752 → (3)

- 25f - 15s = - 1920 → (4)

Add (3) and (4) term by term to eliminate s , that is

- 4f = - 168 ( divide both sides by - 4 )

f = 42

Substitute f = 42 into either of the 2 equations and solve for s

Substituting into (1)

7(42) + 5s = 584

294 + 5s = 584 ( subtract 294 from both sides )

5s = 290 ( divide both sides by 5 )

s = 58

The cost of a bag of flour is $42 and cost of sugar is $58

1gm = 1000mg so 0.1gm = 1000mg

first, convert the weight to kg

160lb * 1kg/2.2lb = 72.7kg

next, the dose

72.7kg * 100mg/kg = 7270mg

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