In a situation where the sample size was 28 while the population standard deviation was increased, what would be the impact on the confidence interval? A) It would become narrower due to using the t distribution
B) It would widen with more values
C) It would become wider due to using the z distribution
D) It would become wider with more dispersion in values

C; It would become wider due to using the z-distribution

Step-by-step explanation:

Mathematically, we go on to look at the formula for confidence interval calculations here

The formula involves multiplying z by the s

which is the z-value and the standard deviation

Increasing the standard deviation value means we are increasing the product of multiplying z and s

This means that we are getting a larger value for the multiplication

Thus, we now have a wider confidence interval value as a result of a larger product

So this means that the CI would become wider due to the usage of the z-distribution

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .